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-x^2+24x-135=0
We add all the numbers together, and all the variables
-1x^2+24x-135=0
a = -1; b = 24; c = -135;
Δ = b2-4ac
Δ = 242-4·(-1)·(-135)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-6}{2*-1}=\frac{-30}{-2} =+15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+6}{2*-1}=\frac{-18}{-2} =+9 $
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